Talk:Varistor

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[edit] Varistor vs. TVS

There are two significant differences between the Varistor and a silicon Transient Voltage Suppressor(TVS). Varistors are typically an order of magnitude more leakier, ie they will drain a battery 10X faster. Also they degrade over time. This shows up after repeated transient events. Mike

Incorporated. Mike: you could have done that yourself. -- Tim Starling 03:22, Oct 24, 2003 (UTC)
What about the other figures of merit? Capacitance, max. energy, etc.?-- Tim Starling 03:26, Oct 24, 2003 (UTC)

I think the comparison is incomplete/misleading, at best. Because MOVs are a bulk-effect device, they tend to be able to absorb more surge energy (joules) for a given size package. A diode-derived design puts all the action at a junction, an inherently thin slice of the device, concentrating the energy/heat that needs to be dissapated, so a diode of a given size is likely to be less able to handle as much energy as a MOV. (Also, can someone supply some links/references so that we can check the details on leakage etc.?)

This source says that the leakage current is similar: http://www.lightningtalks.com/LightningProtection.htm detailed Comparison of Surge Suppression devices

Metal-oxide varistor (MOV)
+ Up to 70 000 Amps surge
+ Lifetime @ 100 Amps, 8x20 uS pulse shape: 1000 surges
- Shunt capacitance >500 pF
- Leakage approximately 10 micro amps

Avalanche diode
+ Lifetime @ 50 Amps, 8x20 uS pulse shape: infinite
+ Shunt capacitance: 50 pF
- Low surge capability: 50 Amps @ 8x20 uS pulse shape
- Leakage approximately 10 micro amps

69.87.203.165 14:11, 9 November 2006 (UTC)

[edit] A capacitor? Hardly!

The lede of the article currently contains the following statement:

and is not a resistor but in fact a capacitor.

This is horsepucky. While many MOVs usually look like capacitors (in the form of flat disks) and have some parasitic capacitance (which can be measured when you're below their threshold voltage), they are most definitely not capacitors in the sense that an Electrical Engineer would typically mean it. Once you're above their threshold voltage, they are primarily resistive, not capacitive. They are non-linear resistors.

If no one objects, I'll (eventually) re-write this part of the lede.

Atlant 11:40, 25 May 2005 (UTC)

Of course they're not capacitors. I rewrote the intro. --Heron 16:47, 25 May 2005 (UTC)
Thanks! Atlant 23:31, 25 May 2005 (UTC)

[edit] Action of Varistors

I dont think the varistor acts as a spark gap, but as a non linear resistor as it says in the first line. Under high applied voltage, it does not breakdown like a gap, but merely goes low resistance, maybe the author was thinking of a miniature gas discharge tube (spark gap). Would anyone like to comment before I alter??Light current 18:57, 9 August 2005 (UTC)

The "spark gap" line is so rubbish that I can't wait for you to delete it - it's gone. --Heron 20:58, 9 August 2005 (UTC)

[edit] Vague intent

I am perplexed by the following quote from the MOV section:

When used in communications lines (such as phone lines used for modems), high capacitance is undesirable since it absorbs high frequency signals, thereby reducing the available bandwidth of the line being protected.

Can someone indicate whether a varistor is part of the problem or part of the solution? Vonkje 08:27, 14 September 2005 (UTC)

The varistor is part of the solution to one problem and part of another problem.
It's part of the solution to the problem of preventing lightning transients (and other electrical disturbances) from getting into the equipment and blowing it up. But any parasitic capacitance of the varistor tends to bypass (short out) high frequencies that the modem depends upon and the voice phone likes to have, so parasitic capacitance is a problem. So our ideal varistor (in such applications) would have no parasitic capacitance (and be free, have infinite impedance below the threshold voltage, and other impossible characteristics :-) ).
Atlant 23:51, 22 February 2006 (UTC)

[edit] Electrical Symbol

Can someone add an electrical symbol to the article? --PeterMarkSmith 08:18, 17 January 2006 (UTC)

I would second this motion. --Matejhowell 22:26, 22 February 2006 (UTC)

[edit] Relationship with polyswitches

I ran across the Polyswitch article (referenced by one article as "resettable fuses"), but I believe that there is some relationship between a varistor and a PTC or NTC resettable fuse/polyswitch. Can further research be done? I don't know enough about both, or maybe it is the internal workings that are different... --Matejhowell 21:27, 1 March 2006 (UTC)

Polyswitches are sort of the inverse device of a varistor: Varistors become low resistance when exposed to a voltage greater than their threshold voltage (so are handy for shorting out/clamping transient voltages) while polyswitches become high resistances when forced to carry a current greater than their threshold current (so they are handy for disconnecting an overcurrent condition). Both devices are self-reseting. You could use them together: The polyswitch in series with the supply and the varistor downstream of the polyswitch in parallel with the load.
Atlant 12:37, 28 March 2006 (UTC)

The article says "Polyswitch (trademark) - a combined varistor and PTC thermistor " but I do not think this is true. A polyswitch is certainly a thermistor, but how exactly is it a varistor? The polyswitch article does not mention anything about "varistors" in any case. I think this reference is inaccurate, but I am not sure. 68.228.0.128 07:13, 7 September 2006 (UTC)

Correct. I made a change; see if you like it.
Atlant 12:29, 7 September 2006 (UTC)

[edit] Varistors in shunt or series?

I thought that if a Varistor protects a circuit from excessive voltage spikes, etc, then surely the resistance would have to INCREASE with an increase in voltage, not the other way around, as is stated towards the middle of the article. I'm still learning this stuff, so can someone please help? —This unsigned comment was added by 203.87.68.209 (talk • contribs) .

Varistors are usually hooked up shunting (in parallel with) a load to be protected. If an over-voltage condition occurs, they decrease rapidly in resistance, shorting out most of the energy of the overvoltage (at least until the point where the energy dissipated within the varistor heats the varistor to the point of destruction). The energy of the transient is dissipated in varistor and the source impedance of the voltage rail.
By the way, you can sign your posts on "talk" pages by including four tildes (~~~~) at the end of your post. When you press "Save page", this will be converted into your username or ip address in a handy Wikilinked format. A timestamp will also be included.
Atlant 12:32, 28 March 2006 (UTC)

[edit] Sacrifice?

When encountering a surge, I have read that MOVs will sacrifice themselves to protect loaded equipment. If this is true, I think it should be included in the article. Chris 13:06, 30 October 2006 (UTC)

Each time a MOV absorbs a surge, it tends to be somewhat degraded. The extent of the degradation depends on the size of the surge (energy in joules) compared to the rating of the device. If the surge is too large, the device may be greatly degraded, or fail, perhaps spectacularly. MOVs tend to fail short -- they do everything possible to sacrifice themselves to protect the load, their mission. 69.87.203.165 14:11, 9 November 2006 (UTC)

[edit] MOV Testing

How can you test your MOV/surge protectors to see if they have been degraded etc?

Ideally, you would first visually inspect the MOVs to see if they appear damaged. But if they look OK or you cannot get access to them, you can test them electrically.

Ideally, you would do I-V curve tracing under various conditions. (More information here: http://www.repairfaq.org/sam/semitest.htm ) And you would study the datasheets, such as the pdf here: http://www.newark.com/NewarkWebCommerce/newark/en_US/endecaSearch/partDetail.jsp;?SKU=09F2091&CMP=KNC-G10000645 )

But if you are just trying to get by, the first thing to do would be to check the leakage current at the highest voltage you can easily and safely attain, perhaps just whatever your ohm-meter puts out. Beyond that, you could use the power line as a voltage source (120VAC). You could very carefully check the leakage current, ideally using a current limiting resistor in case the device you are testing is leaky or shorted. With a rectifier and capacitor, you could generate a higher DC voltage, 170VDC. With another rectifier and capacitor, you could double that to 340VDC. Then with a current limiting resistor of about 200K ohms, you would be able to properly measure the nominal VDC of a MOV under a standard leakage current of about 1mA. The big safety concerns are to make sure nothing has to dissipate too much power and gets too hot or burns up. To not overload your DMM or other test instrument with over-voltage etc. And most important, not to get a shock!

69.87.193.213 00:23, 10 November 2006 (UTC)
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