United States presidential election, 2004, in Rhode Island

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Like all other New England states, Rhode Island was carried by Democratic candidate John F. Kerry, a United States senator from neighboring Massachusetts. Even though President George W. Bush fared better than in 2000, he was anyway overwhelmingly defeated in a traditional Democratic stronghold, winning only 38.67% of the vote to 59.42% for Kerry.


Presidential Candidate Running Mate Party Electoral Vote (EV) Popular Vote (PV)
John Kerry of Massachusetts John Edwards of North Carolina Democrat 4 259,760 59.42%
George W. Bush of Texas Richard Cheney of Wyoming Republican 0 169,046 38.67%
Ralph Nader of Connecticut Peter Camejo Independent 0 4,651 1.06%
David Cobb of California Patricia LaMarche of Maine D.C. Statehood Green 0 1,333 0.30%
Others - - 0 2,344 0.54%
Other elections: 2000, 2004, 2008

Statewide winner in bold. See main article : U.S. presidential election, 2004.

[edit] Results by county

County John F. Kerry George W. Bush Others
Providence 62.6% 144,811 35.6% 82,337 1.8% 4,176
Bristol 58.4% 14,448 39.8% 9,855 1.7% 429
Newport 56.9% 22,992 41.1% 16,622 2.0% 812
Washington 55.4% 34,679 42.4% 26,533 2.3% 1,422
Kent 54.9% 42,830 43.2% 33,699 1.9% 1,489