Uniontown, Alabama

From Wikipedia, the free encyclopedia

Uniontown is a city in Perry County, Alabama in the United States of America. As of the 2000 census, the population of the city is 1,636.

1 Geography
2 Demographics
3 Notable Residents and Natives
4 External links

[edit] Geography

Uniontown is located at 32°26′56″N, 87°30′44″W (32.448984, -87.512287)^GR1.

According to the U.S. Census Bureau, the city has a total area of 3.5 km² (1.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 1,636 people, 617 households, and 433 families residing in the city. The population density was 471.4/km² (1,224.9/mi²). There were 743 housing units at an average density of 214.1/km² (556.3/mi²). The racial makeup of the city was 11.80% White and 88.20% Black or African American. 1.10% of the population were Hispanic or Latino of any race.

There were 617 households out of which 41.2% had children under the age of 18 living with them, 26.1% were married couples living together, 40.8% had a female householder with no husband present, and 29.7% were non-families. 28.0% of all households were made up of individuals and 11.0% had someone living alone who was 65 years of age or older. The average household size was 2.65 and the average family size was 3.27.

In the city the population was spread out with 37.3% under the age of 18, 10.7% from 18 to 24, 22.2% from 25 to 44, 16.1% from 45 to 64, and 13.7% who were 65 years of age or older. The median age was 26 years. For every 100 females there were 72.9 males. For every 100 females age 18 and over, there were 60.8 males.

The median income for a household in the city was $12,386, and the median income for a family was $14,148. Males had a median income of $21,625 versus $14,261 for females. The per capita income for the city was $8,268. About 48.2% of families and 47.4% of the population were below the poverty line, including 60.4% of those under age 18 and 31.9% of those age 65 or over.