Tintah, Minnesota

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Tintah is a city in Traverse County, Minnesota, United States. The population was 79 at the 2000 census.

[edit] Geography

Location of Tintah, Minnesota

According to the United States Census Bureau, the city has a total area of 1.9 km² (0.8 mi²), all land.

[edit] Demographics

As of the census2 of 2000, there were 79 people, 37 households, and 21 families residing in the city. The population density was 40.7/km² (104.7/mi²). There were 45 housing units at an average density of 23.2/km² (59.6/mi²). The racial makeup of the city was 100.00% White.

There were 37 households out of which 24.3% had children under the age of 18 living with them, 43.2% were married couples living together, 10.8% had a female householder with no husband present, and 43.2% were non-families. 40.5% of all households were made up of individuals and 27.0% had someone living alone who was 65 years of age or older. The average household size was 2.14 and the average family size was 2.86.

In the city the population was spread out with 26.6% under the age of 18, 5.1% from 18 to 24, 26.6% from 25 to 44, 12.7% from 45 to 64, and 29.1% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 92.7 males. For every 100 females age 18 and over, there were 87.1 males.

The median income for a household in the city was $15,500, and the median income for a family was $13,125. Males had a median income of $18,750 versus $0 for females. The per capita income for the city was $13,536. There were 36.8% of families and 23.4% of the population living below the poverty line, including no under eighteens and 26.1% of those over 64.

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