Tennant, California

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Tennant is a census-designated place (CDP) in Siskiyou County, California, United States. The population was 63 at the 2000 census.

[edit] Geography

Tennant is located at 41°35′6″N, 121°54′42″W (41.585003, -121.911794)^GR1.

According to the United States Census Bureau, the CDP has a total area of 0.6 km² (0.2 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 63 people, 34 households, and 17 families residing in the CDP. The population density was 110.6/km² (289.7/mi²). There were 96 housing units at an average density of 168.5/km² (441.4/mi²). The racial makeup of the CDP was 88.89% White, 1.59% Native American, 3.17% from other races, and 6.35% from two or more races. Hispanic or Latino of any race were 11.11% of the population.

There were 34 households out of which 8.8% had children under the age of 18 living with them, 38.2% were married couples living together, 11.8% had a female householder with no husband present, and 50.0% were non-families. 44.1% of all households were made up of individuals and 26.5% had someone living alone who was 65 years of age or older. The average household size was 1.85 and the average family size was 2.53.

In the CDP the population was spread out with 12.7% under the age of 18, 3.2% from 18 to 24, 17.5% from 25 to 44, 36.5% from 45 to 64, and 30.2% who were 65 years of age or older. The median age was 56 years. For every 100 females there were 80.0 males. For every 100 females age 18 and over, there were 83.3 males.

The median income for a household in the CDP was $10,750, and the median income for a family was $26,250. Males had a median income of $21,250 versus $0 for females. The per capita income for the CDP was $9,929. There were 31.3% of families and 34.8% of the population living below the poverty line, including 100.0% of under eighteens and 8.3% of those over 64.