Tabor, South Dakota

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Tabor is a town in Bon Homme County, South Dakota, United States. The population was 417 at the 2000 census.

[edit] Geography

Tabor is located at 42°56′52″N, 97°39′29″W (42.947641, -97.658104)^GR1.

According to the United States Census Bureau, the town has a total area of 0.9 km² (0.4 mi²), all land.

Tabor has been assigned the ZIP code 57063 and the FIPS place code 62820.

[edit] Demographics

As of the census^GR2 of 2000, there were 417 people, 188 households, and 124 families residing in the town. The population density was 447.2/km² (1,147.4/mi²). There were 201 housing units at an average density of 215.6/km² (553.1/mi²). The racial makeup of the town was 99.52% White, and 0.48% from two or more races.

There were 188 households out of which 25.0% had children under the age of 18 living with them, 61.7% were married couples living together, 2.7% had a female householder with no husband present, and 34.0% were non-families. 31.9% of all households were made up of individuals and 18.1% had someone living alone who was 65 years of age or older. The average household size was 2.22 and the average family size was 2.81.

In the town the population was spread out with 23.3% under the age of 18, 4.8% from 18 to 24, 26.9% from 25 to 44, 22.5% from 45 to 64, and 22.5% who were 65 years of age or older. The median age was 42 years. For every 100 females there were 88.7 males. For every 100 females age 18 and over, there were 87.1 males.

The median income for a household in the town was $30,694, and the median income for a family was $40,893. Males had a median income of $23,438 versus $22,083 for females. The per capita income for the town was $15,885. About 1.5% of families and 6.5% of the population were below the poverty line, including 4.4% of those under age 18 and 19.1% of those age 65 or over.