Summitville, Ohio

From Wikipedia, the free encyclopedia

Summitville is a village in Columbiana County, Ohio, United States. The population was 108 at the 2000 census.

[edit] Geography

Summitville is located at 40°40′44″N, 80°53′12″W (40.679020, -80.886687)^GR1.

According to the United States Census Bureau, the village has a total area of 2.5 km² (0.9 mi²). 2.4 km² (0.9 mi²) of it is land and 0.1 km² (0.04 mi²) of it (2.11%) is water.

[edit] Demographics

As of the census^GR2 of 2000, there were 108 people, 45 households, and 31 families residing in the village. The population density was 44.8/km² (116.1/mi²). There were 49 housing units at an average density of 20.3/km² (52.7/mi²). The racial makeup of the village was 97.22% White, and 2.78% from two or more races. Hispanic or Latino of any race were 0.93% of the population.

There were 45 households out of which 28.9% had children under the age of 18 living with them, 57.8% were married couples living together, 13.3% had a female householder with no husband present, and 28.9% were non-families. 26.7% of all households were made up of individuals and 15.6% had someone living alone who was 65 years of age or older. The average household size was 2.40 and the average family size was 2.94.

In the village the population was spread out with 26.9% under the age of 18, 5.6% from 18 to 24, 25.9% from 25 to 44, 28.7% from 45 to 64, and 13.0% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 74.2 males. For every 100 females age 18 and over, there were 68.1 males.

The median income for a household in the village was $26,250, and the median income for a family was $38,750. Males had a median income of $31,250 versus $17,143 for females. The per capita income for the village was $17,236. There were 13.3% of families and 15.7% of the population living below the poverty line, including 36.4% of under eighteens and none of those over 64.