Summerhill, Pennsylvania

From Wikipedia, the free encyclopedia

Summerhill is a borough in Cambria County, Pennsylvania, United States. The population was 521 at the 2000 census.

[edit] Geography

Summerhill is located at 40°22′32″N, 78°45′38″W (40.375424, -78.760623)^GR1.

According to the United States Census Bureau, the borough has a total area of 0.8 km² (0.3 mi²). 0.8 km² (0.3 mi²) of it is land and 3.12% is water.

[edit] Demographics

As of the census^GR2 of 2000, there were 521 people, 220 households, and 146 families residing in the borough. The population density was 628.6/km² (1,647.5/mi²). There were 227 housing units at an average density of 273.9/km² (717.8/mi²). The racial makeup of the borough was 99.81% White and 0.19% Asian. Hispanic or Latino of any race were 0.58% of the population.

There were 220 households out of which 27.7% had children under the age of 18 living with them, 55.5% were married couples living together, 10.9% had a female householder with no husband present, and 33.2% were non-families. 32.7% of all households were made up of individuals and 20.5% had someone living alone who was 65 years of age or older. The average household size was 2.36 and the average family size was 3.00.

In the borough the population was spread out with 25.7% under the age of 18, 8.3% from 18 to 24, 25.1% from 25 to 44, 20.3% from 45 to 64, and 20.5% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 86.1 males. For every 100 females age 18 and over, there were 76.7 males.

The median income for a household in the borough was $25,750, and the median income for a family was $38,125. Males had a median income of $29,583 versus $25,313 for females. The per capita income for the borough was $15,013. About 9.7% of families and 13.1% of the population were below the poverty line, including 14.7% of those under age 18 and 19.3% of those age 65 or over.