Sumayyah binte Khabbab
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This is a sahabiyya of Muhammad.
Sumayyah bint Khabbab was the African (Abyssinian) slave of Abu Hudhaifah ibn al-Mughirah and the mother of Ammar ibn Yasir.
She was the seventh one to accept Islam.
Yasir ibn Amir was also a slave to Abu Hudhaifah, so Abu Hudhaifah married him to Sumayyah and they had Ammar, and Abu Hudhaifah freed his slave.
Yasir and his wife and his son were all from the earliest people to accept Islam.
Ibn Ishaq stated in his 'Maghazi' that some men from the family of Ammar ibn Yassar narrated that Sumayyah was punished by the family of al-Mughira because of her Islam. She refused to leave Islam.
Muhammad used to go to Ammar, his mother and his father when they were being punished at al-Abtah, during the month of Ramadhan in Mecca. He would say
Mujahid said "The first ones who showed their Islam in Mecca were seven: the Messenger of Allah, Abu Bakr, Bilal, Khatab, Suhaib, Ammar, Sumayyah." (note that Ali is not mentioned)
As far as the Messenger of Allah and Abu Bakr then their people prevented them from being harmed. As for the others, they [the mushrikin] seized them, dressed them in a suit of armor and cooked them in the sun.
Abu Jahl came to Sumayyah and stabbed her with a spear in her private parts and she died as a result of that. Therefore she was the first 'shaheedah' (martyr) in Islam.
Abu Shaibah and the author Jarir and Mansur and Mujahid… stated it is mursal with an authentic chain.
- Ibn Sa'd narrates with an authentic chain on the authority of Mujahid that the first shaheed in Islam was Sumayyah, the mother of Ammar ibn Yasir. And she was a small old woman. And Abu Jahl was killed on the day of Badr. The Messenger [sall'Allahu aleihi was salam] said to Ammar: "Allah has killed the one who has killed your mother."
