St. Johnsbury (CDP), Vermont
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St. Johnsbury is a census-designated place (CDP) in Caledonia County, Vermont, United States. The population was 6,319 at the 2000 census.
[edit] Geography
According to the United States Census Bureau, the CDP has a total area of 33.9 km² (13.1 mi²). 33.6 km² (13.0 mi²) of it is land and 0.2 km² (0.1 mi²) of it (0.69%) is water.
[edit] Demographics
As of the census2 of 2000, there were 6,319 people, 2,726 households, and 1,561 families residing in the CDP. The population density was 188.0/km² (486.8/mi²). There were 2,985 housing units at an average density of 88.8/km² (230.0/mi²). The racial makeup of the CDP was 96.23% White, 0.47% Black or African American, 0.74% Native American, 0.65% Asian, 0.03% Pacific Islander, 0.27% from other races, and 1.60% from two or more races. Hispanic or Latino of any race were 1.35% of the population.
There were 2,726 households out of which 27.6% had children under the age of 18 living with them, 41.6% were married couples living together, 12.3% had a female householder with no husband present, and 42.7% were non-families. 35.6% of all households were made up of individuals and 16.6% had someone living alone who was 65 years of age or older. The average household size was 2.18 and the average family size was 2.83.
In the CDP the population was spread out with 22.3% under the age of 18, 9.0% from 18 to 24, 25.6% from 25 to 44, 23.2% from 45 to 64, and 19.9% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 93.0 males. For every 100 females age 18 and over, there were 89.4 males.
The median income for a household in the CDP was $26,702, and the median income for a family was $39,890. Males had a median income of $31,454 versus $21,283 for females. The per capita income for the CDP was $16,561. About 12.8% of families and 15.8% of the population were below the poverty line, including 24.3% of those under age 18 and 9.1% of those age 65 or over.