St. Joe, Arkansas

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St. Joe is a town in Searcy County, Arkansas, United States. The population was 85 at the 2000 census.

1 Geography
2 Demographics
3 Notable resident
4 External links

[edit] Geography

St. Joe is located at 36°1′44″N, 92°48′44″W (36.028892, -92.812324)^GR1.

According to the United States Census Bureau, the town has a total area of 2.0 km² (0.8 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 85 people, 41 households, and 23 families residing in the town. The population density was 43.2/km² (111.8/mi²). There were 50 housing units at an average density of 25.4/km² (65.7/mi²). The racial makeup of the town was 92.94% White, 4.71% Native American, and 2.35% from two or more races.

There were 41 households out of which 24.4% had children under the age of 18 living with them, 39.0% were married couples living together, 14.6% had a female householder with no husband present, and 41.5% were non-families. 39.0% of all households were made up of individuals and 12.2% had someone living alone who was 65 years of age or older. The average household size was 2.07 and the average family size was 2.67.

In the town the population was spread out with 21.2% under the age of 18, 8.2% from 18 to 24, 27.1% from 25 to 44, 23.5% from 45 to 64, and 20.0% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 93.2 males. For every 100 females age 18 and over, there were 97.1 males.

The median income for a household in the town was $20,000, and the median income for a family was $36,250. Males had a median income of $20,000 versus $15,625 for females. The per capita income for the town was $12,238. There were no families and 4.1% of the population living below the poverty line, including no under eighteens and none of those over 64.