Talk:Solving quadratic equations with continued fractions

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Why are we only using examples of period 1? Septentrionalis PMAnderson 03:54, 13 December 2006 (UTC)

Your general theorem cannot be true as stated; x2 - 2 has a perfectly good continued fraction for the positive root (and for that matter, the negative root) despite having b = 0; I think I see what is meant, but it's not what is said. Septentrionalis PMAnderson 04:08, 13 December 2006 (UTC)

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