Solebury Township, Pennsylvania
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Solebury Township is a township in Bucks County, Pennsylvania, United States. The population was 7,743 at the 2000 census.
[edit] Geography
According to the United States Census Bureau, the township has a total area of 70.6 km² (27.2 mi²). 69.0 km² (26.6 mi²) of it is land and 1.6 km² (0.6 mi²) of it (2.20%) is water.
[edit] Demographics
As of the census2 of 2000, there were 7,743 people, 3,053 households, and 2,170 families residing in the township. The population density was 112.2/km² (290.6/mi²). There were 3,207 housing units at an average density of 46.5/km² (120.4/mi²).
The racial makeup of the township was:
- 97.12% White
- 0.63% African American
- 0.19% Native American
- 0.85% Asian
- 0.09% Pacific Islander
- 0.35% from other races
- 0.76% from two or more races
- 1.45% Hispanic or Latino
There are 3,053 households:
- 30.4% contain children under the age of 18
- 63.9% are married couples living together
- 5.1% have a female householder with no husband present
- 28.9% were non-families.
- 19.0% of all households were made up of individuals
- 5.5% had someone living alone who was 65 years of age or older.
The average household size was 2.52 and the average family size was 2.94.
Solebury contains citizens of different ages
- 22.0% under the age of 18
- 4.1% from 18 to 24
- 25.8% from 25 to 44
- 36.5% from 45 to 64
- 11.6% who were 65 years of age or older.
The median age was 44 years. For every 100 females there were 99.3 males. For every 100 females age 18 and over, there were 100.4 males.
The median income for a household in the township was $89,005, and the median income for a family was $103,566. Males had a median income of $71,176 versus $42,361 for females. The per capita income for the township was $52,985. About 1.7% of families and 3.1% of the population were below the poverty line, including 4.4% of those under age 18 and 3.5% of those age 65 or over.
