Shickley, Nebraska

From Wikipedia, the free encyclopedia

Shickley is a village in Fillmore County, Nebraska, United States. The population was 376 at the 2000 census.

[edit] Geography

Shickley is located at 40°25′1″N, 97°43′26″W (40.416824, -97.723810)^GR1.

According to the United States Census Bureau, the village has a total area of 0.8 km² (0.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 376 people, 154 households, and 111 families residing in the village. The population density was 500.6/km² (1,280.2/mi²). There were 170 housing units at an average density of 226.3/km² (578.8/mi²). The racial makeup of the village was 97.87% White, 0.27% African American, 0.27% Pacific Islander, 1.33% from other races, and 0.27% from two or more races. Hispanic or Latino of any race were 1.60% of the population.

There were 154 households out of which 35.1% had children under the age of 18 living with them, 65.6% were married couples living together, 3.2% had a female householder with no husband present, and 27.9% were non-families. 24.7% of all households were made up of individuals and 16.9% had someone living alone who was 65 years of age or older. The average household size was 2.44 and the average family size was 2.92.

In the village the population was spread out with 26.6% under the age of 18, 5.1% from 18 to 24, 24.2% from 25 to 44, 22.3% from 45 to 64, and 21.8% who were 65 years of age or older. The median age was 42 years. For every 100 females there were 104.3 males. For every 100 females age 18 and over, there were 101.5 males.

The median income for a household in the village was $43,125, and the median income for a family was $49,750. Males had a median income of $36,875 versus $20,000 for females. The per capita income for the village was $19,257. About 0.9% of families and 3.2% of the population were below the poverty line, including 3.2% of those under age 18 and 1.3% of those age 65 or over.