Shevlin, Minnesota
From Wikipedia, the free encyclopedia
Shevlin is a city in Clearwater County, Minnesota. As of the 2000 census, the city had a population of 160.
[edit] Geography
According to the United States Census Bureau, the city has a total area of 2.1 km² (0.8 mi²), all land.
[edit] Demographics
As of the census2 of 2000, there were 160 people, 69 households, and 40 families residing in the city. The population density was 77.2/km² (201.1/mi²). There were 76 housing units at an average density of 36.7/km² (95.5/mi²). The racial makeup of the city was 96.25% White, 0.62% Native American, and 3.12% from two or more races.
There were 69 households out of which 33.3% had children under the age of 18 living with them, 46.4% were married couples living together, 4.3% had a female householder with no husband present, and 42.0% were non-families. 33.3% of all households were made up of individuals and 10.1% had someone living alone who was 65 years of age or older. The average household size was 2.32 and the average family size was 3.03.
In the city the population was spread out with 25.0% under the age of 18, 8.1% from 18 to 24, 31.9% from 25 to 44, 26.9% from 45 to 64, and 8.1% who were 65 years of age or older. The median age was 37 years. For every 100 females there were 119.2 males. For every 100 females age 18 and over, there were 110.5 males.
The median income for a household in the city was $30,000, and the median income for a family was $37,813. Males had a median income of $73,750 versus $20,000 for females. The per capita income for the city was $20,015. About 6.7% of families and 12.6% of the population were below the poverty line, including 15.6% of those under the age of eighteen and 8.3% of those sixty five or over.
