Shelburn, Indiana

From Wikipedia, the free encyclopedia

Shelburn is a town in Sullivan County, Indiana, United States. The population was 1,268 at the 2000 census.

[edit] Geography

Shelburn is located at 39°10′46″N, 87°23′49″W (39.179506, -87.396900)^GR1.

According to the United States Census Bureau, the town has a total area of 1.7 km² (0.7 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 1,268 people, 510 households, and 350 families residing in the town. The population density was 741.8/km² (1,926.0/mi²). There were 585 housing units at an average density of 342.2/km² (888.6/mi²). The racial makeup of the town was 97.79% White, 0.24% African American, 0.08% Native American, 0.16% Asian, 0.39% from other races, and 1.34% from two or more races. Hispanic or Latino of any race were 0.55% of the population.

There were 510 households out of which 33.3% had children under the age of 18 living with them, 48.0% were married couples living together, 14.7% had a female householder with no husband present, and 31.2% were non-families. 27.8% of all households were made up of individuals and 11.4% had someone living alone who was 65 years of age or older. The average household size was 2.47 and the average family size was 2.96.

In the town the population was spread out with 27.6% under the age of 18, 9.1% from 18 to 24, 26.7% from 25 to 44, 23.9% from 45 to 64, and 12.8% who were 65 years of age or older. The median age was 34 years. For every 100 females there were 94.2 males. For every 100 females age 18 and over, there were 91.3 males.

The median income for a household in the town was $25,714, and the median income for a family was $30,294. Males had a median income of $26,467 versus $20,521 for females. The per capita income for the town was $12,752. About 17.0% of families and 18.0% of the population were below the poverty line, including 24.5% of those under age 18 and 12.7% of those age 65 or over.