Sharpsburg, Georgia

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Sharpsburg is a town in Coweta County, Georgia, United States. The population was 316 at the 2000 census.

[edit] Geography

Sharpsburg is located at 33°20′22″N, 84°39′1″W (33.339337, -84.650155)^GR1.

According to the United States Census Bureau, the town has a total area of 1.4 km² (0.6 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 316 people, 125 households, and 86 families residing in the town. The population density was 221.8/km² (579.0/mi²). There were 127 housing units at an average density of 89.2/km² (232.7/mi²). The racial makeup of the town was 94.94% White, 4.11% African American, 0.32% Native American, 0.32% from other races, and 0.32% from two or more races. Hispanic or Latino of any race were 3.48% of the population.

There were 125 households out of which 34.4% had children under the age of 18 living with them, 60.8% were married couples living together, 5.6% had a female householder with no husband present, and 31.2% were non-families. 25.6% of all households were made up of individuals and 5.6% had someone living alone who was 65 years of age or older. The average household size was 2.53 and the average family size was 3.08.

In the town the population was spread out with 25.6% under the age of 18, 5.7% from 18 to 24, 36.7% from 25 to 44, 25.0% from 45 to 64, and 7.0% who were 65 years of age or older. The median age was 34 years. For every 100 females there were 100.0 males. For every 100 females age 18 and over, there were 104.3 males.

The median income for a household in the town was $55,000, and the median income for a family was $68,750. Males had a median income of $41,932 versus $26,250 for females. The per capita income for the town was $23,169. None of the families and 2.4% of the population were living below the poverty line, including no under eighteens and 22.2% of those over 64.