Shady Grove, Cherokee County, Oklahoma

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Shady Grove is a census-designated place (CDP) in Cherokee County, Oklahoma, United States. The population was 484 at the 2000 census.

[edit] Geography

Shady Grove is located at 35°57′11″N, 95°5′36″W (35.953001, -95.093290)^GR1.

According to the United States Census Bureau, the CDP has a total area of 32.7 km² (12.6 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 484 people, 181 households, and 131 families residing in the CDP. The population density was 14.8/km² (38.4/mi²). There were 200 housing units at an average density of 6.1/km² (15.9/mi²). The racial makeup of the CDP was 57.23% White, 0.41% African American, 35.95% Native American, 0.83% from other races, and 5.58% from two or more races. Hispanic or Latino of any race were 3.93% of the population.

There were 181 households out of which 35.4% had children under the age of 18 living with them, 60.2% were married couples living together, 9.9% had a female householder with no husband present, and 27.1% were non-families. 24.9% of all households were made up of individuals and 8.8% had someone living alone who was 65 years of age or older. The average household size was 2.67 and the average family size was 3.22.

In the CDP the population was spread out with 29.3% under the age of 18, 8.3% from 18 to 24, 30.6% from 25 to 44, 21.3% from 45 to 64, and 10.5% who were 65 years of age or older. The median age was 34 years. For every 100 females there were 91.3 males. For every 100 females age 18 and over, there were 95.4 males.

The median income for a household in the CDP was $27,273, and the median income for a family was $34,196. Males had a median income of $20,938 versus $15,000 for females. The per capita income for the CDP was $11,343. About 15.0% of families and 17.5% of the population were below the poverty line, including 22.8% of those under age 18 and 8.5% of those age 65 or over.