Shady Dale, Georgia

From Wikipedia, the free encyclopedia

Shady Dale is a town in Jasper County, Georgia, United States. The population was 242 at the 2000 census.

[edit] Geography

Shady Dale is located at 33°23′58″N, 83°35′24″W (33.399562, -83.589937)^GR1.

According to the United States Census Bureau, the town has a total area of 2.1 km² (0.8 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 242 people, 88 households, and 60 families residing in the town. The population density was 112.6/km² (290.2/mi²). There were 89 housing units at an average density of 41.4/km² (106.7/mi²). The racial makeup of the town was 65.29% White, 28.10% African American, 6.61% from other races. Hispanic or Latino of any race were 6.61% of the population.

There were 88 households out of which 29.5% had children under the age of 18 living with them, 56.8% were married couples living together, 10.2% had a female householder with no husband present, and 30.7% were non-families. 28.4% of all households were made up of individuals and 12.5% had someone living alone who was 65 years of age or older. The average household size was 2.75 and the average family size was 3.41.

In the town the population was spread out with 27.7% under the age of 18, 7.9% from 18 to 24, 26.9% from 25 to 44, 25.2% from 45 to 64, and 12.4% who were 65 years of age or older. The median age was 35 years. For every 100 females there were 101.7 males. For every 100 females age 18 and over, there were 88.2 males.

The median income for a household in the town was $35,469, and the median income for a family was $36,042. Males had a median income of $31,000 versus $21,607 for females. The per capita income for the town was $10,791. About 10.5% of families and 14.6% of the population were below the poverty line, including 14.3% of those under the age of eighteen and 19.2% of those sixty five or over.