Rockville, Nebraska

From Wikipedia, the free encyclopedia

Rockville is a village in Sherman County, Nebraska, United States. The population was 111 at the 2000 census.

[edit] Geography

Rockville is located at 41°7′9″N, 98°49′53″W (41.119229, -98.831359)^GR1.

According to the United States Census Bureau, the village has a total area of 0.6 km² (0.2 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 111 people, 53 households, and 29 families residing in the village. The population density was 194.8/km² (495.0/mi²). There were 62 housing units at an average density of 108.8/km² (276.5/mi²). The racial makeup of the village was 100.00% White. Hispanic or Latino of any race were 1.80% of the population.

There were 53 households out of which 18.9% had children under the age of 18 living with them, 52.8% were married couples living together, 1.9% had a female householder with no husband present, and 43.4% were non-families. 35.8% of all households were made up of individuals and 17.0% had someone living alone who was 65 years of age or older. The average household size was 2.09 and the average family size was 2.70.

In the village the population was spread out with 19.8% under the age of 18, 3.6% from 18 to 24, 24.3% from 25 to 44, 29.7% from 45 to 64, and 22.5% who were 65 years of age or older. The median age was 48 years. For every 100 females there were 109.4 males. For every 100 females age 18 and over, there were 111.9 males.

The median income for a household in the village was $27,813, and the median income for a family was $32,188. Males had a median income of $23,958 versus $25,625 for females. The per capita income for the village was $15,708. There were no families and 8.4% of the population living below the poverty line, including no under eighteens and 19.4% of those over 64.