Ravenna, Texas

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Ravenna is a city in Fannin County, Texas, United States. The population was 215 at the 2000 census.

1 Geography
2 Demographics
3 Education
4 External links

[edit] Geography

Ravenna is located at 33°40′18″N, 96°14′30″W (33.671759, -96.241773)^GR1.

According to the United States Census Bureau, the city has a total area of 3.1 km² (1.2 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 215 people, 86 households, and 65 families residing in the city. The population density was 68.6/km² (177.6/mi²). There were 94 housing units at an average density of 30.0/km² (77.6/mi²). The racial makeup of the city was 97.67% White, 0.93% from other races, and 1.40% from two or more races. Hispanic or Latino of any race were 1.40% of the population.

There were 86 households out of which 32.6% had children under the age of 18 living with them, 65.1% were married couples living together, 5.8% had a female householder with no husband present, and 24.4% were non-families. 22.1% of all households were made up of individuals and 15.1% had someone living alone who was 65 years of age or older. The average household size was 2.50 and the average family size was 2.91.

In the city the population was spread out with 27.0% under the age of 18, 6.0% from 18 to 24, 27.0% from 25 to 44, 23.3% from 45 to 64, and 16.7% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 100.9 males. For every 100 females age 18 and over, there were 96.3 males.

The median income for a household in the city was $31,875, and the median income for a family was $42,778. Males had a median income of $33,125 versus $17,500 for females. The per capita income for the city was $13,581. About 12.1% of families and 17.5% of the population were below the poverty line, including 28.8% of those under the age of eighteen and 17.1% of those sixty five or over.