Panama, Nebraska

From Wikipedia, the free encyclopedia

Panama is a village in Lancaster County, Nebraska, United States. The population was 253 at the 2000 census.

[edit] Geography

Panama is located at 40°35′52″N, 96°30′38″W (40.597640, -96.510599)^GR1.

According to the United States Census Bureau, the village has a total area of 0.7 km² (0.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 253 people, 97 households, and 77 families residing in the village. The population density was 361.8/km² (943.2/mi²). There were 101 housing units at an average density of 144.4/km² (376.5/mi²). The racial makeup of the village was 98.81% White, 0.79% African American and 0.40% Asian. Hispanic or Latino of any race were 0.79% of the population.

There were 97 households out of which 42.3% had children under the age of 18 living with them, 71.1% were married couples living together, 5.2% had a female householder with no husband present, and 20.6% were non-families. 16.5% of all households were made up of individuals and 8.2% had someone living alone who was 65 years of age or older. The average household size was 2.61 and the average family size was 2.96.

In the village the population was spread out with 30.4% under the age of 18, 4.7% from 18 to 24, 30.0% from 25 to 44, 22.1% from 45 to 64, and 12.6% who were 65 years of age or older. The median age was 37 years. For every 100 females there were 93.1 males. For every 100 females age 18 and over, there were 87.2 males.

The median income for a household in the village was $47,841, and the median income for a family was $50,625. Males had a median income of $36,563 versus $18,750 for females. The per capita income for the village was $17,596. None of the families and 1.4% of the population were living below the poverty line.