Orangeville, Utah

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For other places with the same name, see Orangeville.

Orangeville is a city in Emery County, Utah, United States. The population was 1,398 at the 2000 census.

[edit] Geography

Orangeville is located at 39°13′37″N, 111°3′22″W (39.226956, -111.055977)^GR1.

According to the United States Census Bureau, the city has a total area of 3.4 km² (1.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 1,398 people, 430 households, and 350 families residing in the city. The population density was 415.2/km² (1,073.5/mi²). There were 471 housing units at an average density of 139.9/km² (361.7/mi²). The racial makeup of the city was 98.43% White, 0.07% African American, 0.43% Native American, 0.14% Asian, 0.50% from other races, and 0.43% from two or more races. Hispanic or Latino of any race were 1.22% of the population.

There were 430 households out of which 51.4% had children under the age of 18 living with them, 73.7% were married couples living together, 4.7% had a female householder with no husband present, and 18.4% were non-families. 16.7% of all households were made up of individuals and 6.0% had someone living alone who was 65 years of age or older. The average household size was 3.25 and the average family size was 3.68.

In the city the population was spread out with 38.4% under the age of 18, 8.6% from 18 to 24, 25.9% from 25 to 44, 19.2% from 45 to 64, and 7.9% who were 65 years of age or older. The median age was 29 years. For every 100 females there were 97.2 males. For every 100 females age 18 and over, there were 95.7 males.

The median income for a household in the city was $45,057, and the median income for a family was $48,942. Males had a median income of $43,382 versus $21,667 for females. The per capita income for the city was $15,160. About 4.2% of families and 7.0% of the population were below the poverty line, including 7.8% of those under age 18 and 3.5% of those age 65 or over.