Ohiowa, Nebraska

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Ohiowa is a village in Fillmore County, Nebraska, United States. The population was 142 at the 2000 census.

1 Geography
2 Demographics
3 Notable residents
4 External links

[edit] Geography

Ohiowa is located at 40°24′51″N, 97°27′8″W (40.414057, -97.452190)^GR1.

According to the United States Census Bureau, the village has a total area of 0.6 km² (0.2 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 142 people, 69 households, and 34 families residing in the village. The population density was 219.3/km² (573.4/mi²). There were 78 housing units at an average density of 120.5/km² (315.0/mi²). The racial makeup of the village was 94.37% White, 0.70% African American, 2.11% from other races, and 2.82% from two or more races. Hispanic or Latino of any race were 7.04% of the population.

There were 69 households out of which 18.8% had children under the age of 18 living with them, 42.0% were married couples living together, 7.2% had a female householder with no husband present, and 50.7% were non-families. 46.4% of all households were made up of individuals and 30.4% had someone living alone who was 65 years of age or older. The average household size was 2.06 and the average family size was 2.97.

In the village the population was spread out with 19.0% under the age of 18, 6.3% from 18 to 24, 26.1% from 25 to 44, 19.0% from 45 to 64, and 29.6% who were 65 years of age or older. The median age was 44 years. For every 100 females there were 84.4 males. For every 100 females age 18 and over, there were 76.9 males.

The median income for a household in the village was $20,625, and the median income for a family was $28,125. Males had a median income of $23,333 versus $13,750 for females. The per capita income for the village was $12,526. There were 25.8% of families and 33.1% of the population living below the poverty line, including 73.1% of under eighteens and 22.0% of those over 64.