Newark, Arkansas

From Wikipedia, the free encyclopedia

Newark is a city in Independence County, Arkansas, United States. The population was 1,219 at the 2000 census.

[edit] Geography

Newark is located at 35°42′9″N, 91°26′41″W (35.702637, -91.444798)^GR1.

According to the United States Census Bureau, the city has a total area of 4.5 km² (1.8 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 1,219 people, 500 households, and 345 families residing in the city. The population density was 268.9/km² (696.9/mi²). There were 562 housing units at an average density of 124.0/km² (321.3/mi²). The racial makeup of the city was 96.55% White, 0.66% Black or African American, 0.98% Native American, 0.49% Asian, 0.08% Pacific Islander, 0.08% from other races, and 1.15% from two or more races. 0.90% of the population were Hispanic or Latino of any race.

There were 500 households out of which 35.8% had children under the age of 18 living with them, 55.0% were married couples living together, 10.6% had a female householder with no husband present, and 31.0% were non-families. 29.0% of all households were made up of individuals and 18.0% had someone living alone who was 65 years of age or older. The average household size was 2.44 and the average family size was 3.01.

In the city the population was spread out with 26.7% under the age of 18, 8.8% from 18 to 24, 27.6% from 25 to 44, 21.5% from 45 to 64, and 15.4% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 87.0 males. For every 100 females age 18 and over, there were 83.6 males.

The median income for a household in the city was $28,239, and the median income for a family was $34,545. Males had a median income of $27,404 versus $17,692 for females. The per capita income for the city was $14,392. About 9.1% of families and 14.2% of the population were below the poverty line, including 18.5% of those under age 18 and 20.1% of those age 65 or over.