Talk:Metric tensor (general relativity)

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  • Discussion of metric as gravitational potential (+ link to weak-field approximation).
  • Raising and lowering indices.
  • Cut down the 'volume' section (and shift that derivation to another article - or just get rid of it).

[edit] Cut material

I cut out the material on the volume form which properly belongs at volume form. Here it is for reference:

Let [g] be the matrix of elements gμν. Matrix [g] is symmetric, so due to a corollary of the spectral theorem, there exists an orthogonal transformation matrix Λ which diagonalizes [g], e.g.

D = \Lambda^\top [g] \Lambda
where D is a diagonal matrix whose diagonal elements are eigenvalues of [g]: Dαα = λα. (Note that Λ can be chosen so that the eigenvalues are in numerical order, D00 being the smallest.) Then there is a diagonal matrix V which "unitizes" D, i.e. which applies the mapping \lambda_\alpha \mapsto \mbox{sgn} (\lambda_\alpha) to the diagonal elements of D. Such matrix V has diagonal elements
V_{\alpha\alpha} = \left\{ \begin{matrix}  {1 \over \sqrt{| \lambda_\alpha |}} & \quad \mbox{if} \, \lambda_\alpha \ne 0 \\  0 & \quad \mbox{if} \, \lambda_\alpha = 0 \end{matrix} \right.
Then
[\eta] = V^\top \Lambda^\top [g] \Lambda V
and for a given manifold, the trace of [η] will be the same for all points and is referred to as the signature of the metric. (A signature of +2 is synonymous with a signature of (− + + +). ) This matrix [η] has the components of the Minkowski metric, which means that the manifold is, at each one of its points, locally smooth. The matrix (V \Lambda)^\top is a Jacobian (a multivariate differential, or push forward) which transforms [η] to [g],
[g] = V \Lambda [\eta] \Lambda^\top V^\top
and taking determinants
g := \mbox{det}([g]) = \mbox{det}\,(V \Lambda) \,\mbox{det}([\eta]) \,\mbox{det}(\Lambda^\top V^\top)
= \mbox{det}^2 (V \Lambda) \, \mbox{det}([\eta]), \
g = -\mbox{det}^2 (V \Lambda), \
\mbox{det}(V \Lambda) = \sqrt{-g},
but due to a property of diffeomorphisms, a volume element dx0dx1dx2dx3 whose factors are components of an orthonormal basis (locally), when transformed to components dx^{\bar\mu}, has the determinant of the Jacobian matrix J as conversion factor:
G = dx^0 dx^1 dx^2 dx^3 = \mbox{det}(J) \, dx^{\bar 0} dx^{\bar 1} dx^{\bar 2} dx^{\bar 3}.
See also volume form.

-- Fropuff 18:02, 22 February 2006 (UTC)

[edit] Amusing Veblen/Einstein anecdote

See Sign convention ---CH 01:54, 25 May 2006 (UTC)