Talk:Method of undetermined coefficients

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I can solve A_n = A A_{n-1} + B A_{n-2}, but how do I go about solving A_n = A A_{n-1} + B A_{n-2} + k?

Many thanks in advance for your help. Pcb21| Pete 13:49, 22 July 2005 (UTC)

Is that different "A"s you're talking about, "A" and "A_n"? Reorder the equation to get A_n - a A_{n-1} - b A_{n-2} = k. Find solutions for the inhomogeneous and the homogeneous difference equation. Notice that you have a difference eq'n, not a differential eq'n. Probably this is too late, as the stochastics class is already over (right guess?) 134.83.1.225 15:35, 12 December 2005 (UTC)

[edit] Strange Roots yield different answers

Should it be noted that when differential equations yield repeated or imaginary roots the form of the 'guess' changes? --Bmalicoat 05:26, 1 March 2006 (UTC)

Yes, it should. Also, more of the theory should be explained. Ruakh 05:56, 1 March 2006 (UTC)

[edit] particular solution

The examples make a pat description of an extremely simple problem, making it difficult to see how one would provide forms for the particular solutions of more complex equations. The difficult example, on the other hand, is overly complex for some cases.