Menan, Idaho

From Wikipedia, the free encyclopedia

Menan is a city in Jefferson County, Idaho, United States. The population was 707 at the 2000 census.

[edit] Geography

Menan is located at 43°43′14″N, 111°59′42″W (43.720520, -111.994914)^GR1.

According to the United States Census Bureau, the city has a total area of 2.5 km² (0.9 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 707 people, 220 households, and 187 families residing in the city. The population density was 287.3/km² (745.0/mi²). There were 233 housing units at an average density of 94.7/km² (245.5/mi²). The racial makeup of the city was 87.13% White, 0.14% Native American, 0.14% Pacific Islander, 11.32% from other races, and 1.27% from two or more races. Hispanic or Latino of any race were 14.43% of the population.

There were 220 households out of which 44.5% had children under the age of 18 living with them, 72.7% were married couples living together, 7.3% had a female householder with no husband present, and 15.0% were non-families. 11.4% of all households were made up of individuals and 7.7% had someone living alone who was 65 years of age or older. The average household size was 3.21 and the average family size was 3.51.

In the city the population was spread out with 34.1% under the age of 18, 9.5% from 18 to 24, 24.2% from 25 to 44, 20.4% from 45 to 64, and 11.9% who were 65 years of age or older. The median age was 30 years. For every 100 females there were 94.2 males. For every 100 females age 18 and over, there were 95.8 males.

The median income for a household in the city was $36,406, and the median income for a family was $40,357. Males had a median income of $29,531 versus $21,750 for females. The per capita income for the city was $13,464. About 7.3% of families and 11.9% of the population were below the poverty line, including 17.0% of those under age 18 and 6.1% of those age 65 or over.