Maynard, Iowa

From Wikipedia, the free encyclopedia

Maynard is a city in Fayette County, Iowa, United States. The population was 500 at the 2000 census.

[edit] Geography

Maynard is located at 42°46′28″N, 91°52′42″W (42.774493, -91.878293)^GR1.

According to the United States Census Bureau, the city has a total area of 2.6 km² (1.0 mi²). 2.6 km² (1.0 mi²) of it is land and 0.1 km² (0.04 mi²) of it (2.94%) is water.

[edit] Demographics

As of the census^GR2 of 2000, there were 500 people, 222 households, and 138 families residing in the city. The population density was 195.0/km² (504.2/mi²). There were 238 housing units at an average density of 92.8/km² (240.0/mi²). The racial makeup of the city was 100.00% White. Hispanic or Latino of any race were 0.20% of the population.

There were 222 households out of which 29.7% had children under the age of 18 living with them, 51.4% were married couples living together, 7.7% had a female householder with no husband present, and 37.4% were non-families. 34.7% of all households were made up of individuals and 21.6% had someone living alone who was 65 years of age or older. The average household size was 2.25 and the average family size was 2.92.

In the city the population was spread out with 24.0% under the age of 18, 6.6% from 18 to 24, 26.8% from 25 to 44, 20.6% from 45 to 64, and 22.0% who were 65 years of age or older. The median age was 41 years. For every 100 females there were 106.6 males. For every 100 females age 18 and over, there were 99.0 males.

The median income for a household in the city was $32,639, and the median income for a family was $40,833. Males had a median income of $28,929 versus $26,667 for females. The per capita income for the city was $15,779. About 4.4% of families and 8.1% of the population were below the poverty line, including 8.5% of those under age 18 and 9.8% of those age 65 or over.