Maplehurst, Wisconsin
From Wikipedia, the free encyclopedia
Maplehurst is a town in Taylor County, Wisconsin, United States. The population was 359 at the 2000 census.
[edit] Geography
According to the United States Census Bureau, the town has a total area of 93.1 km² (35.9 mi²). 93.0 km² (35.9 mi²) of it is land and 0.1 km² (0.04 mi²) of it (0.06%) is water.
[edit] Demographics
As of the census2 of 2000, there were 359 people, 133 households, and 98 families residing in the town. The population density was 3.9/km² (10.0/mi²). There were 144 housing units at an average density of 1.5/km² (4.0/mi²). The racial makeup of the town was 97.77% White, 0.56% Native American, 0.28% Asian, and 1.39% from two or more races. Hispanic or Latino of any race were 1.67% of the population.
There were 133 households out of which 34.6% had children under the age of 18 living with them, 59.4% were married couples living together, 9.0% had a female householder with no husband present, and 26.3% were non-families. 21.1% of all households were made up of individuals and 9.8% had someone living alone who was 65 years of age or older. The average household size was 2.70 and the average family size was 3.14.
In the town the population was spread out with 28.4% under the age of 18, 8.4% from 18 to 24, 27.3% from 25 to 44, 25.3% from 45 to 64, and 10.6% who were 65 years of age or older. The median age was 35 years. For every 100 females there were 118.9 males. For every 100 females age 18 and over, there were 108.9 males.
The median income for a household in the town was $29,375, and the median income for a family was $32,813. Males had a median income of $26,429 versus $20,000 for females. The per capita income for the town was $13,062. About 11.7% of families and 19.2% of the population were below the poverty line, including 26.4% of those under age 18 and 8.5% of those age 65 or over.
