Manville, Wyoming

From Wikipedia, the free encyclopedia

Manville is a town in Niobrara County, Wyoming, United States. The population was 101 at the 2000 census.

[edit] Geography

Manville is located at 42°46′46″N, 104°36′59″W (42.779467, -104.616319)^GR1.

According to the United States Census Bureau, the town has a total area of 0.7 km² (0.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 101 people, 49 households, and 32 families residing in the town. The population density was 139.3/km² (357.8/mi²). There were 54 housing units at an average density of 74.5/km² (191.3/mi²). The racial makeup of the town was 100.00% White.

There were 49 households out of which 18.4% had children under the age of 18 living with them, 59.2% were married couples living together, 4.1% had a female householder with no husband present, and 32.7% were non-families. 28.6% of all households were made up of individuals and 16.3% had someone living alone who was 65 years of age or older. The average household size was 2.06 and the average family size was 2.52.

In the town the population was spread out with 17.8% under the age of 18, 3.0% from 18 to 24, 16.8% from 25 to 44, 27.7% from 45 to 64, and 34.7% who were 65 years of age or older. The median age was 58 years. For every 100 females there were 90.6 males. For every 100 females age 18 and over, there were 102.4 males.

The median income for a household in the town was $15,833, and the median income for a family was $28,750. Males had a median income of $41,250 versus $21,250 for females. The per capita income for the town was $11,386. There were 10.5% of families and 13.6% of the population living below the poverty line, including no under eighteens and 26.7% of those over 64.