Linear dynamical system
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In a linear dynamical system, the variation of a state vector (an N-dimensional vector denoted ) equals a constant matrix (denoted ) multiplied by . This variation can take two forms: either as a flow, in which varies continuously with time
or (less commonly) as a mapping, in which varies in discrete steps
These equations are linear in the following sense: if and are two valid solutions, then so is any linear combination of the two solutions, e.g., where α and β are any two scalars. It is important to note that the matrix need not be symmetric.
Linear dynamical systems can be solved exactly, in contrast to most nonlinear ones. Occasionally, a nonlinear system can be solved exactly by a change of variables to a linear system. Moreover, the solutions of (almost) any nonlinear system can be well-approximated by an equivalent linear system near its fixed points. Hence, understanding linear systems and their solutions is a crucial first step to understanding the more complex nonlinear systems.
[edit] Solution of linear dynamical systems
If the initial vector is aligned with a right eigenvector of the matrix , the dynamics are simple
where λk is the corresponding eigenvalue; the solution of this equation is
as may be confirmed by substitution.
If A is diagonalizable, then any vector in an N-dimensional space can be represented by a linear combination of the right and left eigenvectors (denoted ) of the matrix .
Therefore, the general solution for is a linear combination of the individual solutions for the right eigenvectors
Similar considerations apply to the discrete mappings.
[edit] Classification in two dimensions
The roots of the characteristic polynomial det(A - λI) are the eigenvalues of A. The sign and relation of these roots, λn, to each other may be used to determine the stability of the dynamical system
For a 2-dimensional system, the characteristic polynomial is of the form λ2 − τλ + Δ = 0 where τ is the trace and Δ is the determinant of A. Thus the two roots are in the form:
Note also that Δ = λ1λ2 and τ = λ1 + λ2. Thus if Δ < 0 then the eigenvalues are of opposite sign, and the fixed point is a saddle. If Δ > 0 then the eigenvalues are of the same sign. Therefore if τ > 0 both are positive and the point is unstable, and if τ < 0 then both are negative and the point is stable. The discriminant will tell you if the point is nodal or spiral (i.e. if the eigenvalues are real or complex).