Lincolnshire, Kentucky

From Wikipedia, the free encyclopedia

Lincolnshire is a city in Jefferson County, Kentucky, United States. The population was 154 at the 2000 census.

[edit] Geography

Lincolnshire is located at 38°13′27″N, 85°37′15″W (38.224052, -85.620893)^GR1.

According to the United States Census Bureau, the city has a total area of 0.1 km² it is all land and none of it is covered by water.

[edit] Demographics

As of the census^GR2 of 2000, there were 154 people, 61 households, and 43 families residing in the city. The population density was 1,486.5/km² (3,455.7/mi²). There were 63 housing units at an average density of 608.1/km² (1,413.7/mi²). The racial makeup of the city was 96.75% White, and 3.25% from two or more races. Hispanic or Latino of any race were 1.95% of the population.

There were 61 households out of which 24.6% had children under the age of 18 living with them, 65.6% were married couples living together, 3.3% had a female householder with no husband present, and 27.9% were non-families. 23.0% of all households were made up of individuals and 11.5% had someone living alone who was 65 years of age or older. The average household size was 2.52 and the average family size was 3.00.

In the city the population was spread out with 18.2% under the age of 18, 9.1% from 18 to 24, 21.4% from 25 to 44, 31.2% from 45 to 64, and 20.1% who were 65 years of age or older. The median age was 46 years. For every 100 females there were 111.0 males. For every 100 females age 18 and over, there were 103.2 males.

The median income for a household in the city was $66,667, and the median income for a family was $66,250. Males had a median income of $51,250 versus $26,250 for females. The per capita income for the city was $29,200. About 3.9% of families and 5.2% of the population were below the poverty line, including 11.8% of those under the age of eighteen and none of those sixty five or over.