Lenapah, Oklahoma

From Wikipedia, the free encyclopedia

Lenapah is a town in Nowata County, Oklahoma, United States. The population was 298 at the 2000 census.

[edit] Geography

Lenapah is located at 36°51′6″N, 95°38′12″W (36.851617, -95.636572)^GR1.

According to the United States Census Bureau, the town has a total area of 1.0 km² (0.4 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 298 people, 109 households, and 81 families residing in the town. The population density was 295.0/km² (770.5/mi²). There were 139 housing units at an average density of 137.6/km² (359.4/mi²). The racial makeup of the town was 66.78% White, 7.72% African American, 16.78% Native American, 1.01% from other races, and 7.72% from two or more races. Hispanic or Latino of any race were 1.34% of the population.

There were 109 households out of which 40.4% had children under the age of 18 living with them, 56.9% were married couples living together, 13.8% had a female householder with no husband present, and 24.8% were non-families. 22.0% of all households were made up of individuals and 14.7% had someone living alone who was 65 years of age or older. The average household size was 2.73 and the average family size was 3.12.

In the town the population was spread out with 31.9% under the age of 18, 8.1% from 18 to 24, 28.9% from 25 to 44, 18.5% from 45 to 64, and 12.8% who were 65 years of age or older. The median age was 34 years. For every 100 females there were 102.7 males. For every 100 females age 18 and over, there were 89.7 males.

The median income for a household in the town was $29,688, and the median income for a family was $35,357. Males had a median income of $31,250 versus $22,000 for females. The per capita income for the town was $14,087. About 14.5% of families and 17.3% of the population were below the poverty line, including 18.5% of those under the age of eighteen and 22.0% of those sixty five or over.