Talk:Leibniz formula (determinant)

From Wikipedia, the free encyclopedia

You have new messages (last change).

Is the "physisists formula" usinge the Levi-Civita symbols correct? As I understand it, there is a 1/n! missing.

[edit] A part of the proof is missing

In the proof, the reason why the n-tuples are reduced to the permutations is missing. The reason why the ordered n-tuples (k_1, \dots, k_n) are reduced to the permutations is because F is alternating, and therefore F(E^{k_1}, \dots, E^{k_n}) is zero for all n-tuples (k_1, \dots, k_n) that repeat indices. Jeff Wu 01:11, 6 December 2006 (UTC)

Retrieved from "http://en.wikipedia.org../../../l/e/i/Talk%7ELeibniz_formula_%28determinant%29_45d4.html"