Laurel Hill, Florida

From Wikipedia, the free encyclopedia

Laurel Hill is a city in Okaloosa County, Florida, United States. The population was 549 at the 2000 census. As of 2004, the population recorded by the U.S. Census Bureau is 576 [1].

[edit] Geography

Laurel Hill is located at 30°57′55″N, 86°27′33″W (30.965369, -86.459149)^GR1.

According to the United States Census Bureau, the city has a total area of 8.1 km² (3.1 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 549 people, 223 households, and 158 families residing in the city. The population density was 67.5/km² (174.9/mi²). There were 254 housing units at an average density of 31.2/km² (80.9/mi²). The racial makeup of the city was 77.23% White, 21.68% African American, 0.18% Native American, 0.73% from other races, and 0.18% from two or more races. Hispanic or Latino of any race were 1.09% of the population.

There were 223 households out of which 30.9% had children under the age of 18 living with them, 49.8% were married couples living together, 17.0% had a female householder with no husband present, and 29.1% were non-families. 25.6% of all households were made up of individuals and 11.7% had someone living alone who was 65 years of age or older. The average household size was 2.46 and the average family size was 2.93.

In the city the population was spread out with 26.8% under the age of 18, 5.8% from 18 to 24, 27.7% from 25 to 44, 24.0% from 45 to 64, and 15.7% who were 65 years of age or older. The median age was 39 years. For every 100 females there were 90.0 males. For every 100 females age 18 and over, there were 85.3 males.

The median income for a household in the city was $25,385, and the median income for a family was $28,281. Males had a median income of $25,809 versus $17,500 for females. The per capita income for the city was $12,949. About 18.0% of families and 21.6% of the population were below the poverty line, including 25.2% of those under age 18 and 9.4% of those age 65 or over.