Kirby, Wyoming

From Wikipedia, the free encyclopedia

Kirby is a town in Hot Springs County, Wyoming, United States. The population was 57 at the 2000 census.

[edit] Geography

Kirby is located at 43°48′11″N, 108°10′49″W (43.803003, -108.180310)^GR1.

According to the United States Census Bureau, the town has a total area of 0.3 km² (0.1 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 57 people, 29 households, and 14 families residing in the town. The population density was 200.1/km² (524.5/mi²). There were 37 housing units at an average density of 129.9/km² (340.5/mi²). The racial makeup of the town was 94.74% White, 3.51% Asian, and 1.75% from two or more races. Hispanic or Latino of any race were 7.02% of the population.

There were 29 households out of which 17.2% had children under the age of 18 living with them, 37.9% were married couples living together, 6.9% had a female householder with no husband present, and 48.3% were non-families. 48.3% of all households were made up of individuals and 17.2% had someone living alone who was 65 years of age or older. The average household size was 1.97 and the average family size was 2.67.

In the town the population was spread out with 17.5% under the age of 18, 5.3% from 18 to 24, 24.6% from 25 to 44, 40.4% from 45 to 64, and 12.3% who were 65 years of age or older. The median age was 46 years. For every 100 females there were 78.1 males. For every 100 females age 18 and over, there were 62.1 males.

The median income for a household in the town was $18,750, and the median income for a family was $43,125. Males had a median income of $18,750 versus $30,417 for females. The per capita income for the town was $19,137. There were 18.2% of families and 12.2% of the population living below the poverty line, including no under eighteens and 50.0% of those over 64.