Kermit, West Virginia

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Kermit is a town in Mingo County, West Virginia, United States. The population was 209 at the 2000 census.

[edit] Geography

Kermit was located at 37°50′27″N, 82°24′34″W (37.840783, -82.409465)^GR1 in 2000.

According to the United States Census Bureau, the town has a total area of 0.7 km² (0.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 209 people, 89 households, and 60 families residing in the town. The population density was 298.9/km² (780.9/mi²). There were 99 housing units at an average density of 141.6/km² (369.9/mi²). The racial makeup of the town was 99.52% White and 0.48% Native American.

There were 89 households out of which 30.3% had children under the age of 18 living with them, 59.6% were married couples living together, 9.0% had a female householder with no husband present, and 31.5% were non-families. 31.5% of all households were made up of individuals and 19.1% had someone living alone who was 65 years of age or older. The average household size was 2.35 and the average family size was 2.95.

In the town the population was spread out with 23.0% under the age of 18, 5.7% from 18 to 24, 30.6% from 25 to 44, 22.0% from 45 to 64, and 18.7% who were 65 years of age or older. The median age was 39 years. For every 100 females there were 77.1 males. For every 100 females age 18 and over, there were 85.1 males.

The median income for a household in the town was $31,500, and the median income for a family was $40,000. Males had a median income of $36,250 versus $16,250 for females. The per capita income for the town was $14,695. About 4.0% of families and 10.1% of the population were below the poverty line, including 7.0% of those under the age of eighteen and 7.9% of those sixty five or over.