Kent, Iowa

From Wikipedia, the free encyclopedia

Kent is a city in Union County, Iowa, United States. The population was 52 at the 2000 census.

[edit] Geography

Kent is located at 40°57′11″N, 94°27′24″W (40.953106, -94.456566)^GR1.

According to the United States Census Bureau, the city has a total area of 0.7 km² (0.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 52 people, 23 households, and 14 families residing in the city. The population density was 77.2/km² (201.1/mi²). There were 27 housing units at an average density of 40.1/km² (104.4/mi²). The racial makeup of the city was 100.00% White.

There were 23 households out of which 21.7% had children under the age of 18 living with them, 47.8% were married couples living together, and 39.1% were non-families. 30.4% of all households were made up of individuals and 8.7% had someone living alone who was 65 years of age or older. The average household size was 2.26 and the average family size was 2.64.

In the city the population was spread out with 17.3% under the age of 18, 9.6% from 18 to 24, 32.7% from 25 to 44, 28.8% from 45 to 64, and 11.5% who were 65 years of age or older. The median age was 42 years. For every 100 females there were 116.7 males. For every 100 females age 18 and over, there were 126.3 males.

The median income for a household in the city was $27,917, and the median income for a family was $22,188. Males had a median income of $23,125 versus $26,250 for females. The per capita income for the city was $13,529. There were 18.2% of families and 17.1% of the population living below the poverty line, including no under eighteens and none of those over 64.