Kealakekua, Hawai'i

From Wikipedia, the free encyclopedia

Kealakekua is a census-designated place (CDP) in Hawaiʻi County, Hawaiʻi, United States. The population was 1,645 at the 2000 census.

[edit] Geography

Kealakekua is located at 19°31′35″N, 155°55′22″W (19.526436, -155.922891)^GR1.

According to the United States Census Bureau, the CDP has a total area of 19.5 km² (7.5 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 1,645 people, 639 households, and 423 families residing in the CDP. The population density was 84.2/km² (218.1/mi²). There were 692 housing units at an average density of 35.4/km² (91.7/mi²). The racial makeup of the CDP was 24.74% White, 0.73% African American, 0.67% Native American, 36.84% Asian, 7.23% Pacific Islander, 2.07% from other races, and 27.72% from two or more races. Hispanic or Latino of any race were 9.18% of the population.

There were 639 households out of which 25.5% had children under the age of 18 living with them, 49.0% were married couples living together, 12.2% had a female householder with no husband present, and 33.8% were non-families. 26.9% of all households were made up of individuals and 9.2% had someone living alone who was 65 years of age or older. The average household size was 2.57 and the average family size was 3.10.

In the CDP the population was spread out with 22.1% under the age of 18, 7.7% from 18 to 24, 25.3% from 25 to 44, 27.5% from 45 to 64, and 17.3% who were 65 years of age or older. The median age was 42 years. For every 100 females there were 91.5 males. For every 100 females age 18 and over, there were 89.2 males.

The median income for a household in the CDP was $38,026, and the median income for a family was $45,192. Males had a median income of $29,333 versus $25,000 for females. The per capita income for the CDP was $21,495. About 9.2% of families and 13.7% of the population were below the poverty line, including 17.1% of those under age 18 and 6.3% of those age 65 or over.