Jeffersonville, Kentucky

From Wikipedia, the free encyclopedia

Jeffersonville is a city in Montgomery County, Kentucky, United States. The population was 1,804 at the 2000 census.

[edit] Geography

Jeffersonville is located at 37°58′9″N, 83°49′28″W (37.969148, -83.824466)^GR1.

According to the United States Census Bureau, the city has a total area of 7.8 km² (3.0 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 1,804 people, 682 households, and 525 families residing in the city. The population density was 230.6/km² (596.6/mi²). There were 738 housing units at an average density of 94.4/km² (244.0/mi²). The racial makeup of the city was 99.06% White, 0.11% African American, 0.11% Native American, 0.17% Asian, and 0.55% from two or more races. Hispanic or Latino of any race were 0.94% of the population.

There were 682 households out of which 38.4% had children under the age of 18 living with them, 61.6% were married couples living together, 12.3% had a female householder with no husband present, and 22.9% were non-families. 19.6% of all households were made up of individuals and 8.8% had someone living alone who was 65 years of age or older. The average household size was 2.65 and the average family size was 3.02.

In the city the population was spread out with 26.6% under the age of 18, 8.6% from 18 to 24, 31.4% from 25 to 44, 22.4% from 45 to 64, and 11.0% who were 65 years of age or older. The median age was 34 years. For every 100 females there were 101.3 males. For every 100 females age 18 and over, there were 96.1 males.

The median income for a household in the city was $29,392, and the median income for a family was $33,355. Males had a median income of $26,492 versus $17,576 for females. The per capita income for the city was $13,254. About 14.7% of families and 18.5% of the population were below the poverty line, including 22.7% of those under age 18 and 19.7% of those age 65 or over.