Jefferson, Georgia

From Wikipedia, the free encyclopedia

Jefferson is a city in Jackson County, Georgia, United States. The population was 3,825 at the 2000 census. The city is the county seat of Jackson County^GR6.

[edit] Geography

Jefferson is located at 34°7′36″N, 83°35′25″W (34.126736, -83.590297)^GR1.

According to the United States Census Bureau, the city has a total area of 49.2 km² (19.0 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 3,825 people, 1,415 households, and 1,047 families residing in the city. The population density was 77.8/km² (201.6/mi²). There were 1,522 housing units at an average density of 31.0/km² (80.2/mi²). The racial makeup of the city was 80.44% White, 16.05% African American, 1.20% Asian, 1.15% from other races, and 1.15% from two or more races. Hispanic or Latino of any race were 4.21% of the population.

There were 1,415 households out of which 37.2% had children under the age of 18 living with them, 55.0% were married couples living together, 15.6% had a female householder with no husband present, and 26.0% were non-families. 23.3% of all households were made up of individuals and 9.2% had someone living alone who was 65 years of age or older. The average household size was 2.67 and the average family size was 3.15.

In the city the population was spread out with 28.1% under the age of 18, 8.0% from 18 to 24, 30.1% from 25 to 44, 21.4% from 45 to 64, and 12.5% who were 65 years of age or older. The median age was 35 years. For every 100 females there were 88.7 males. For every 100 females age 18 and over, there were 84.0 males.

The median income for a household in the city was $41,146, and the median income for a family was $46,755. Males had a median income of $33,512 versus $25,250 for females. The per capita income for the city was $18,456. About 12.5% of families and 15.2% of the population were below the poverty line, including 21.8% of those under age 18 and 10.8% of those age 65 or over.