Hershey, Nebraska

From Wikipedia, the free encyclopedia

Hershey is a village in Lincoln County, Nebraska, United States. The population was 572 at the 2000 census.

[edit] Geography

Hershey is located at 41°9′29″N, 101°0′6″W (41.158118, -101.001721)^GR1.

According to the United States Census Bureau, the village has a total area of 1.3 km² (0.5 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 572 people, 232 households, and 167 families residing in the village. The population density was 441.7/km² (1,142.4/mi²). There were 249 housing units at an average density of 192.3/km² (497.3/mi²). The racial makeup of the village was 91.61% White, 0.17% African American, 0.52% Asian, 6.82% from other races, and 0.87% from two or more races. Hispanic or Latino of any race were 9.62% of the population.

There were 232 households out of which 34.9% had children under the age of 18 living with them, 57.8% were married couples living together, 10.8% had a female householder with no husband present, and 27.6% were non-families. 23.7% of all households were made up of individuals and 11.6% had someone living alone who was 65 years of age or older. The average household size was 2.47 and the average family size was 2.93.

In the village the population was spread out with 28.1% under the age of 18, 7.2% from 18 to 24, 25.7% from 25 to 44, 26.0% from 45 to 64, and 12.9% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 88.8 males. For every 100 females age 18 and over, there were 89.4 males.

The median income for a household in the village was $36,875, and the median income for a family was $43,000. Males had a median income of $31,500 versus $16,848 for females. The per capita income for the village was $15,791. About 9.7% of families and 9.9% of the population were below the poverty line, including 8.7% of those under age 18 and 11.9% of those age 65 or over.