Hendley, Nebraska

From Wikipedia, the free encyclopedia

Hendley is a village in Furnas County, Nebraska, United States. The population was 38 at the 2000 census.

[edit] Geography

Hendley is located at 40°7′51″N, 99°58′10″W (40.130849, -99.969427)^GR1.

According to the United States Census Bureau, the village has a total area of 0.5 km² (0.2 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 38 people, 16 households, and 9 families residing in the village. The population density was 69.9/km² (179.2/mi²). There were 22 housing units at an average density of 40.4/km² (103.8/mi²). The racial makeup of the village was 92.11% White, 5.26% from other races, and 2.63% from two or more races. Hispanic or Latino of any race were 7.89% of the population.

There were 16 households out of which 25.0% had children under the age of 18 living with them, 50.0% were married couples living together, 6.3% had a female householder with no husband present, and 43.8% were non-families. 37.5% of all households were made up of individuals and 18.8% had someone living alone who was 65 years of age or older. The average household size was 2.38 and the average family size was 3.22.

In the village the population was spread out with 23.7% under the age of 18, 10.5% from 18 to 24, 26.3% from 25 to 44, 26.3% from 45 to 64, and 13.2% who were 65 years of age or older. The median age was 41 years. For every 100 females there were 81.0 males. For every 100 females age 18 and over, there were 107.1 males.

The median income for a household in the village was $30,000, and the median income for a family was $48,750. Males had a median income of $50,625 versus $13,750 for females. The per capita income for the village was $13,550. There were 33.3% of families and 26.5% of the population living below the poverty line, including 30.8% of under eighteens and none of those over 64.