Hardy, Nebraska

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Hardy is a village in Nuckolls County, Nebraska, United States. The population was 179 at the 2000 census.

[edit] Geography

Hardy is located at 40°0′34″N, 97°55′35″W (40.009417, -97.926397)^GR1.

According to the United States Census Bureau, the village has a total area of 1.6 km² (0.6 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 179 people, 68 households, and 46 families residing in the village. The population density was 113.3/km² (293.6/mi²). There were 89 housing units at an average density of 56.3/km² (146.0/mi²). The racial makeup of the village was 100.00% White.

There were 68 households out of which 32.4% had children under the age of 18 living with them, 55.9% were married couples living together, 5.9% had a female householder with no husband present, and 30.9% were non-families. 26.5% of all households were made up of individuals and 16.2% had someone living alone who was 65 years of age or older. The average household size was 2.63 and the average family size was 3.17.

In the village the population was spread out with 32.4% under the age of 18, 8.4% from 18 to 24, 19.6% from 25 to 44, 26.3% from 45 to 64, and 13.4% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 126.6 males. For every 100 females age 18 and over, there were 112.3 males.

The median income for a household in the village was $28,750, and the median income for a family was $31,250. Males had a median income of $16,250 versus $15,500 for females. The per capita income for the village was $13,539. About 17.0% of families and 18.4% of the population were below the poverty line, including 26.8% of those under the age of eighteen and 17.2% of those sixty five or over.