Talk:Green's theorem

From Wikipedia, the free encyclopedia

1 Do we expect a proof?
2 Stokes
3 Alternative Notation
4 Stray if
5 Other form
6 Must have been written by math people...
7 A Burp?
8 A Burp!
9 Notation
10 A mistake in the article ?

[edit] Do we expect a proof?

Do we expect to see a proof in an encyclopedia? Billlion 14:20, 13 Sep 2004 (UTC)

See WikiProject Mathematics. In this case I think the proof can be ommitted. The thereom is easy to understand and the proof is quite long and technical, so does not contribute to understanding of the theorem. Contrast this with Cantor's diagonal argument where the proof is neccessary for understanding the theorem MathMartin 10:36, 14 Sep 2004 (UTC)

personally I'm Glad the proof is there, "do we expect a proof in an encyclopedia..." of course, this encyclopedia should contain everything possible and more...

[edit] Stokes

What about Stokes theorem

[edit] Alternative Notation

The alternative notation given doesn't indicate the integral is calculated using the positive orientation of C. It just tells the integral is calculated over a closed curve. To indicate positive orientation, an arrow pointing in the counter-clockwise direction is usually drawn in the circle over the integral symbol.

[edit] Stray if

"If it can be shown that if

$\int_{C} L\, dx = \iint_{D} \left(- \frac{\partial L}{\partial y}\right) dA\qquad\mathrm{(1)}$

and

$\int_{C} M\, dy = \iint_{D} \left(\frac{\partial M}{\partial x}\right)\, dA\qquad\mathrm{(2)}$

are true, then Green's theorem is proven." [emphasis added on instance of "if" under discusssion]

The quoted sentences says that:
(it can be shown that if (1) and (2) are true) implies (Green's theorem is proven)
(if (1) and (2) are true) implies (Green's theorem is proven)
"If (1) and (2) are true" doesn't parse correctly.
It should read "If it can be shown that (1) and (2) are true, then Green's theorem is proven." This means that (1) and (2) together imply Green's theorem; this is true. The bold "if" is stray and makes the "sentence" not wrong so much as not a valid sentence. For the record, the statement remains true if the other "if" is pulled instead, but one definitely needs to go. --130.39.152.206 22:29, 19 April 2006 (UTC)

[edit] Other form

This is the curl-circulation (tangential) form. Might be nice to have the flux-divergence (normal) version mentioned, too. Revolver 17:48, 27 April 2006 (UTC)

[edit] Must have been written by math people...

Not a single mention of curl or circulation. Amazing. Revolver 17:55, 27 April 2006 (UTC)

Green's theorem is just a projection down to the plane of Stokes' theorem. It's trivial conceptually given Stokes' theorem, so explaining it intuitively is pretty much a waste of time. --130.39.152.206 01:26, 30 April 2006 (UTC)

Yup, everything is trivial once you understand it, so there's no point in explaining anything. Spoken like a true math dweeb. Revolver 21:43, 3 May 2006 (UTC)

Hey, anonymous, I seriously hope this isn't your idea of an "intuitive explanation" (taken from Stokes' theorem:

The classical Kelvin-Stokes theorem:

$\int_{\Sigma} \nabla \times \mathbf{F} \cdot d\mathbf{\Sigma} = \int_{\partial\Sigma} \mathbf{F} \cdot d \mathbf{r},$

which relates the surface integral of the curl of a vector field over a surface $Σ$ in Euclidean 3 space to the line integral of the vector field over its boundary, is a special case of the general Stokes theorem (with n = 2) once we identify a vector field with a 1 form using the metric on Euclidean 3 space. It can be rewritten for the student unacquainted with forms as

$\iint\limits_{\Sigma}\left(\frac{\partial R}{\partial y}-\frac{\partial Q}{\partial z}\right)\,dydz+\left(\frac{\partial P}{\partial z}-\frac{\partial R}{\partial x}\right)\,dzdx+\left(\frac{\partial Q}{\partial x}-\frac{\partial P}{\partial y}\right)\,dxdy=\oint\limits_{\partial\Sigma}P\,dx+Q\,dy+R\,dz$

where P, Q and R are the components of F.

Oh, yeah, clear as mud. It just POPS right out at the reader how the curl is really the "circulation density" at a point, and so all Green's (Stoke's) theorem is saying is that if you "add up" all the "microscopic circulation density" inside a region, you just get the net circulation along the boundary of the region. In other words, it's just like the ordinary FTC you learned in Calc I. But I suppose such an explanation is just too "obvious" for you, and the protracted terms of partial derivatives above must be much more illuminating. Revolver 21:56, 3 May 2006 (UTC)

You might as well hand them Chapter 10 of Baby Rudin and tell them it's obvious what's going on. Revolver 21:57, 3 May 2006 (UTC)

I am the previously anonymous user (130.39.152.206). "Math dweeb" is an ad hominem attack and therefore inappropriate. In general, your tone is not exactly civil discourse; a calm and reasoned approach is usually better for achieving one's objectives, as assorted clichés point out.

I stand by what I said despite your (likely intentional) misreading. Green's theorem is vastly easier to understand as the projection onto the plane of Stokes' theorem, which basically everyone learns two days later, anyway. Perhaps you should help out at Stokes' theorem if you feel it is not explained well. --CalculatinAvatar 19:19, 4 May 2006 (UTC)

[edit] A Burp?

Does anyone else think the burp analogy is a bit silly for an encyclopedia? - Arsian120 05:52, 17 September 2006 (UTC)

[edit] A Burp!

Well, in that it implies the discharge of gas from the G.I. tract, the burp is socially inappropriate in some settings. However, it is a pictureseque and useful learning tool. I don't think the analogy fully captures the essence of Green's theorem, but it helps me visualize the content of a volume passing through a region. That's good enough for me to vote to retain the burp analogy. 151.200.241.233 12:30, 3 October 2006 (UTC)

[edit] Notation

I'm intrigued by the notation. An integral sign with a little capital letter C at its base. An integral sign with a (possibly directed) circle written over the big curvy S there. The full import of two integral signs written side by side. The full meaning of the partial derivative inside the integral. Ah! The sweet mystery of mathematical notation. All of which is left as an exercise for the reader to grasp. If you a math whiz, the notation is obvious. If you ain't, it ain't. 151.200.241.233 12:30, 3 October 2006 (UTC)

[edit] A mistake in the article ?

Quoting:

"In physics, Green's theorem is mostly used to solve two-dimensional flow integrals, stating that the sum of fluid outflows at any point inside a volume is equal to the total outflow summed about an enclosing area."

I just read at http://www.math.gatech.edu/~carlen/2507/notes/vectorCalc/vectorfields.html It says that Greene's theorem is used for calculating Work done over a closed curve, and that the divergence theorem is used for calculating fluxes.

i.e. integral over an area D of curlF (which is the version stated in the article) gives the work done by F when going through the closed path C, and not the total flux.

Retrieved from "http://en.wikipedia.org../../../g/r/e/Talk%7EGreen%27s_theorem_da32.html"