Funk, Nebraska

From Wikipedia, the free encyclopedia

Funk is a village in Phelps County, Nebraska, United States. The population was 204 at the 2000 census.

[edit] Geography

Funk is located at 40°27′49″N, 99°14′60″W (40.463724, -99.249915)^GR1.

According to the United States Census Bureau, the village has a total area of 0.7 km² (0.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 204 people, 77 households, and 65 families residing in the village. The population density was 291.7/km² (769.7/mi²). There were 82 housing units at an average density of 117.3/km² (309.4/mi²). The racial makeup of the village was 98.04% White, 0.49% Asian, 0.98% from other races, and 0.49% from two or more races. Hispanic or Latino of any race were 1.47% of the population.

There were 77 households out of which 37.7% had children under the age of 18 living with them, 74.0% were married couples living together, 10.4% had a female householder with no husband present, and 14.3% were non-families. 14.3% of all households were made up of individuals and 7.8% had someone living alone who was 65 years of age or older. The average household size was 2.65 and the average family size was 2.92.

In the village the population was spread out with 29.9% under the age of 18, 3.9% from 18 to 24, 22.5% from 25 to 44, 25.0% from 45 to 64, and 18.6% who were 65 years of age or older. The median age was 42 years. For every 100 females there were 98.1 males. For every 100 females age 18 and over, there were 88.2 males.

The median income for a household in the village was $36,250, and the median income for a family was $43,333. Males had a median income of $22,292 versus $20,833 for females. The per capita income for the village was $15,658. About 7.1% of families and 15.3% of the population were below the poverty line, including 32.7% of those under the age of eighteen and 4.3% of those sixty five or over.