Fundamental theorem of Riemannian geometry

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In Riemannian geometry, the fundamental theorem of Riemannian geometry states that given a Riemannian manifold (or pseudo-Riemannian manifold) there is a unique torsion-free connection preserving the metric tensor. Such a connection is called a Levi-Civita connection.

More precisely:

Let (M,g) be a Riemannian manifold (or pseudo-Riemannian manifold) then there is a unique connection \nabla which satisfies the following conditions:

  1. for any vector fields X,Y,Z we have Xg(Y,Z)=g(\nabla_X Y,Z)+g(Y,\nabla_X Z), where Xg(Y,Z) denotes the derivative of function g(Y,Z) along vector field X.
  2. for any vector fields X,Y we have \nabla_XY-\nabla_YX=[X,Y],
    where [X,Y] = XYYX denotes the Lie brackets for vector fields X,Y .
The following technical proof presents a formula for Christoffel symbols of the connection in a local coordinate system. For a given metric this set of equations can become rather complicated. There are quicker and simpler methods to obtain the Christoffel symbols for a given metric, e.g. using the action integral and the associated Euler-Lagrange equations.

[edit] Proof

In this proof we use Einstein notation.

Consider the local coordinate system x^i,\ i=1,2,...,m=\dim(M) and let us denote by {\mathbf e}_i={\partial\over\partial x^i} the field of basis frames.

The components g_{i\;j} are real numbers of the metric tensor applied to a basis, i.e.

g_{i j} \ \stackrel{\mathrm{def}}{=}\  {\mathbf g}({\mathbf e}_i,{\mathbf e}_j)

To specify the connection it is enough to specify the Christoffel symbols Γkij.

Since {\mathbf e}_i are coordinate vector fields we have that

[{\mathbf e}_i,{\mathbf e}_j]={\partial^2\over\partial x^j\partial x^i}-{\partial^2\over\partial x^i\partial x^j}=0

for all i and j. Therefore the second property is equivalent to

\nabla_{{\mathbf e}_i}{{\mathbf e}_j}-\nabla_{{\mathbf e}_j}{{\mathbf e}_i}=0,\ \which is equivalent to \ \   \Gamma^k {}_{ij}=\Gamma^k {}_{ji} for all i,j and k.

The first property of the Levi-Civita connection (above) then is equivalent to:

\frac{\partial g_{ij}}{\partial x^k} =  \Gamma^a {}_{k i} g_{aj} + \Gamma^a {}_{k j} g_{i a}.

This gives the unique relation between the Christoffel symbols (defining the covariant derivative) and the metric tensor components.

We can invert this equation and express the Christoffel symbols with a little trick, by writing this equation three times with a handy choice of the indices

\quad \frac{\partial g_{ij}}{\partial x^k} =          +\Gamma^a {}_{ki} g_{aj}           +\Gamma^a {}_{k j} g_{i a}
\quad \frac{\partial g_{ik}}{\partial x^j} =          +\Gamma^a {}_{ji} g_{ak}           +\Gamma^a {}_{jk} g_{i a}
- \frac{\partial g_{jk}}{\partial x^i} =          -\Gamma^a {}_{ij} g_{ak}          -\Gamma^a {}_{i k} g_{j a}

By adding, most of the terms on the right hand side cancel and we are left with

g_{i a} \Gamma^a {}_{kj} =     \frac{1}{2} \left(     \frac{\partial g_{ij}}{\partial x^k}     +\frac{\partial g_{ik}}{\partial x^j}     -\frac{\partial g_{jk}}{\partial x^i}     \right)

Or with the inverse of \mathbf g, defined as (using the Kronecker delta)

g^{k i} g_{i l}= \delta^k {}_l\,

we write the Christoffel symbols as

\Gamma^i {}_{kj} =            \frac12   g^{i a} \left(     \frac{\partial g_{aj}}{\partial x^k}     +\frac{\partial g_{ak}}{\partial x^j}     -\frac{\partial g_{jk}}{\partial x^a} \right)

In other words, the Christoffel symbols (and hence the covariant derivative) are completely determined by the metric, through equations involving the derivative of the metric.

[edit] See also

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