Talk:Free radical addition

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The radicals should not have negative charges.

The discussion text seems correct. However, there is some ambiguity in the "Br.-radical" which suggests that perhaps the radical is negatively charged. Also, in the illustration, the radicals are clearly marked as being negatively charged. The neutral peroxide molecule does not break into two negatively charged radicals. That indicates a net input of two electrons. The radicals are neutral, and the illustration should be changed to reflect this.

[edit] Does not show anti-Markovnikov

Perhaps a better picture demonstrating that the reaction causes the Br to go to the less substituted carbon atom of the alkene would better illustrate the anti-Markovnikov regiochemistry. Andrew4010 04:44, 21 November 2006 (UTC)