Talk:Fixed point (mathematics)

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The claim that "f(x) = x + 1" has no fixed point in the reals implies that there is a complex number for which it does have a fixed point. There isn't one, is there? I mean, assuming that we restrict ourselves to numbers and the normal interpretation of "=" and "+", x+1 has no fixed points, right?

It does not imply that. There are other things besides reals and complex numbers to which addition of 1 may be done. Transfinite cardinals, for example. Michael Hardy 28 June 2005 20:17 (UTC)

Also, when using IEEE 754 floating point numbers ("doubles"), repeatedly adding 1 to any non-integer value (or an integer between -2^52 and +2^53) eventually converges on the integer 2^53. So you could say that (one) fixed point of "f(x) = x + 1" is x=2^53. --70.189.77.59 04:07, 15 October 2006 (UTC)

[edit] Image

The image used in this article is of the function sin(x), which is rather confusing given that the text next to it is about cos(x). It should probably be changed. Quendus 12:51, 15 October 2006 (UTC)